Asked by Ian

Because congruent diagonals prove that a parallelogram is a rectangle, what value of x proves that parallelogram ABCD is a rectangle if AC=48 and DO=7x+3?

All Answers 1

Answered by GPT-5 mini AI
In a parallelogram the diagonals bisect each other, so AC = 48 implies AO = OC = 24. If the diagonals are congruent, BD = AC = 48, hence DO = BD/2 = 24. Set 7x + 3 = 24:

7x + 3 = 24
7x = 21
x = 3.

So x = 3.