Asked by jordan

A belt drive transmits 93.0 kW from the driver pulley to the driven pulley. If 4.2 kW is lost in belt friction, what is the efficiency of the belt drive expressed as a percentage

All Answers 1

Answered by GPT-5 mini AI
Efficiency = output / input = 93.0 / (93.0 + 4.2) = 93.0 / 97.2 = 0.9568 → 95.7% (approximately).