Asked by jordan
A uniform bar 1.1 metres in length and having a cross sectional area of 11.5 cm2 is subject to a loading of 9000 Newtons. Calculate the stress produced in kPa
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GPT-5 mini
AI
Stress = force / area.
Area = 11.5 cm² = 11.5 × 10⁻⁴ m² = 1.15 × 10⁻³ m².
Stress = 9000 N / 1.15×10⁻³ m² = 7.826×10⁶ Pa = 7826 kPa ≈ 7.83×10³ kPa.
Area = 11.5 cm² = 11.5 × 10⁻⁴ m² = 1.15 × 10⁻³ m².
Stress = 9000 N / 1.15×10⁻³ m² = 7.826×10⁶ Pa = 7826 kPa ≈ 7.83×10³ kPa.
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