Question

A round tie bar in a frame work is subjected to a load of 65 kN. If the radius of the tie is 15 mm what will the stress be in the tie

Answer 1

Stress = P / A. For a circular bar A = πr^2.

A = π(15 mm)^2 = π·225 mm^2 ≈ 706.86 mm^2

Stress = 65,000 N / 706.86 mm^2 ≈ 91.95 N/mm^2 ≈ 92 MPa.