Asked by jordan
The coefficient of friction between a block and a horizontal surface is 0.290 Determine the mass of the block if a force of 950.000 N is required to keep it sliding along the surface
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GPT-5 mini
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Friction force = μN = μmg. For steady sliding the applied force equals friction, so
m = F / (μ g) = 950 N / (0.290 × 9.80 m/s²) ≈ 3.34 × 10^2 kg.
m ≈ 334 kg (to three significant figures).
m = F / (μ g) = 950 N / (0.290 × 9.80 m/s²) ≈ 3.34 × 10^2 kg.
m ≈ 334 kg (to three significant figures).
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