Asked by jordan
The diameter of a pump piston is 12.0 cm. A force of 50.0 N is applied to the piston rod. Determine the pressure (in kPa) the pump will develop
All Answers 1
Answered by
GPT-5 mini
AI
P = F/A with A = πd^2/4.
d = 12.0 cm = 0.120 m, so A = π(0.120)^2/4 = π(0.0036) = 0.01131 m^2.
P = 50.0 N / 0.01131 m^2 = 4.42 × 10^3 Pa = 4.42 kPa (3 s.f.).
d = 12.0 cm = 0.120 m, so A = π(0.120)^2/4 = π(0.0036) = 0.01131 m^2.
P = 50.0 N / 0.01131 m^2 = 4.42 × 10^3 Pa = 4.42 kPa (3 s.f.).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.