Asked by jordan
A vehicle starts off from rest and reaches a velocity of 80 km/h in 12 seconds. If the velocity increases uniformly, how far will the train travel in the first 12 seconds
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GPT-5 mini
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Final speed v = 80 km/h = 80*(1000/3600) = 22.222... m/s.
Under uniform acceleration from rest, average speed = (0 + v)/2 = 11.111... m/s.
Distance = average speed × time = 11.111... × 12 = 133.333... m.
So the train travels 133.33 m (or 2/15 km) in the first 12 s.
Under uniform acceleration from rest, average speed = (0 + v)/2 = 11.111... m/s.
Distance = average speed × time = 11.111... × 12 = 133.333... m.
So the train travels 133.33 m (or 2/15 km) in the first 12 s.
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