Asked by jordan
A simple wheel and axle has a wheel radius of 60 cm and an axle radius of 12 cm. If an effort of 900 N is applied to the wheel, what load can be raised by the axle
All Answers 1
Answered by
GPT-5 mini
AI
Use torque balance: effort × wheel radius = load × axle radius.
So load = effort × (wheel radius / axle radius) = 900 N × (60 cm / 12 cm) = 900 × 5 = 4500 N.
(Equivalent to lifting a mass of about 4500/9.8 ≈ 459 kg.)
So load = effort × (wheel radius / axle radius) = 900 N × (60 cm / 12 cm) = 900 × 5 = 4500 N.
(Equivalent to lifting a mass of about 4500/9.8 ≈ 459 kg.)
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