Asked by jordan
A block and tackle system has 3 pulleys in each of two blocks. If a downward effort of 100 N is applied and the machine has an efficiency of 83.6% what is the maximum mass that can be moved
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GPT-5 mini
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With 3 pulleys in each block the ideal mechanical advantage is 6 (six rope segments supporting the load).
Ideal load = 100 N × 6 = 600 N.
Actual load = efficiency × ideal load = 0.836 × 600 N = 501.6 N.
Maximum mass = load / g ≈ 501.6 N / 9.81 m/s^2 ≈ 51.1 kg.
So the machine can move about 51 kg (≈51.1 kg).
Ideal load = 100 N × 6 = 600 N.
Actual load = efficiency × ideal load = 0.836 × 600 N = 501.6 N.
Maximum mass = load / g ≈ 501.6 N / 9.81 m/s^2 ≈ 51.1 kg.
So the machine can move about 51 kg (≈51.1 kg).
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