f= (7t^-5)^1/2
f'= 1/2 ( )^-1/2 * (-5*7t^-6)
If f(t) = square root of 7/t^5. Find f'(x) and f'(2)
2 answers
the answer is not correct. I input
f'= 1/2 (7t^-5)^-1/2 * (-5*7t^-6)and its incorrect. Did I input the wrong answer?
f'= 1/2 (7t^-5)^-1/2 * (-5*7t^-6)and its incorrect. Did I input the wrong answer?
1 answer