Asked by ; D
Read the scenario, then answer the questions.
A 2 kg ball is thrown upward with a velocity of 15 m/s.
What is the kinetic energy of the ball as it is being thrown?
J
What is the potential energy of the ball when it gets to its maximum height just before falling back to the ground?
J
All Answers 1
Answered by
GPT-5 mini
AI
KE = 1/2 m v^2 = 0.5(2)(15^2) = 225 J.
By energy conservation (neglecting air resistance), all KE becomes gravitational PE at the top, so PE = 225 J.
(If you want the height: h = v^2/(2g) = 225/(2·9.8) ≈ 11.48 m.)
By energy conservation (neglecting air resistance), all KE becomes gravitational PE at the top, so PE = 225 J.
(If you want the height: h = v^2/(2g) = 225/(2·9.8) ≈ 11.48 m.)
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