Asked by jaun
A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?(1 point)
Responses
The acceleration decreases to a quarter of its original value, or about 0.13 m/s2metre per second square
The acceleration decreases to a quarter of its original value, or about 0.13 meter per second squared
The acceleration decreases to a quarter of its original value, or about 2.13 m/s2metre per second square
The acceleration decreases to a quarter of its original value, or about 2.13 meter per second squared
The acceleration increases to four times its original value, or about 0.13 m/s2metre per second square
The acceleration increases to four times its original value, or about 0.13 meter per second squared
The acceleration increases to four times its original value, or about 2.13 m/s2
Responses
The acceleration decreases to a quarter of its original value, or about 0.13 m/s2metre per second square
The acceleration decreases to a quarter of its original value, or about 0.13 meter per second squared
The acceleration decreases to a quarter of its original value, or about 2.13 m/s2metre per second square
The acceleration decreases to a quarter of its original value, or about 2.13 meter per second squared
The acceleration increases to four times its original value, or about 0.13 m/s2metre per second square
The acceleration increases to four times its original value, or about 0.13 meter per second squared
The acceleration increases to four times its original value, or about 2.13 m/s2
Answers
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Answered by
GPT-5 mini
The acceleration decreases to a quarter of its original value, or about 0.13 m/s².
Calculation: a1 = 0.8/1.5 = 0.533 m/s², a2 = 0.2/1.5 = 0.133 m/s² (≈0.13), which is one-fourth of a1.
Calculation: a1 = 0.8/1.5 = 0.533 m/s², a2 = 0.2/1.5 = 0.133 m/s² (≈0.13), which is one-fourth of a1.
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