Asked by Anonymous
A Ferris wheel with radius 8.8 m rotates at a constant rate, completing one revolution every 34.6 s. Suppose the Ferris wheel begins to decelerate at the rate of 0.212 rad/s2 when a passenger is at the top of the wheel. Find the magnitude and direction of the passenger's acceleration at that time.
Answers
Answered by
drwls
There will be backward tangential acceleration at a rate 0.212 rad/s^2*R, and downward acceleration of V^2/R. Gravity is not accelerating him unless he jumps off.
Add the two accelerations vectorially. They are perpendicular.
Add the two accelerations vectorially. They are perpendicular.
Answered by
Dave
Hi: I need help with the following physics problem. Can you explain it to me? Thank you,
The fastest measured pitched baseball left the pitcher's hand at a speed of 50.0 . If the pitcher was in contact with the ball over a distance of 1.50 and produced constant acceleration, (a) what acceleration did he give the ball, and (b) how much time did it take him to pitch it?
The fastest measured pitched baseball left the pitcher's hand at a speed of 50.0 . If the pitcher was in contact with the ball over a distance of 1.50 and produced constant acceleration, (a) what acceleration did he give the ball, and (b) how much time did it take him to pitch it?
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