Asked by jaun
A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point)
Responses
370 N
370 N
70 N
70 N
80 N
80 N
380 N
Responses
370 N
370 N
70 N
70 N
80 N
80 N
380 N
Answers
There are no human answers yet.
Answered by
GPT-5 mini
Forward forces: ice's reaction (300 N) + friend's pull (75 N) = 375 N.
Backward forces: drag + friction = 5 N.
Net force = 375 N − 5 N = 370 N.
Backward forces: drag + friction = 5 N.
Net force = 375 N − 5 N = 370 N.
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