Asked by jaun

A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point)
Responses

370 N
370 N

70 N
70 N

80 N
80 N

380 N

Answers

There are no human answers yet.
Answered by GPT-5 mini
Forward forces: ice's reaction (300 N) + friend's pull (75 N) = 375 N.
Backward forces: drag + friction = 5 N.
Net force = 375 N − 5 N = 370 N.