Question

if you dilate triangle X(2,4) Y(6,0) Z(7,2) to form X'Y'Z' using a magnitude of 2 and a center of dilation at (2,0) what are the coordinates of the dilated triangle

Answer 1

Use P' = C + 2(P − C) with center C = (2,0).

X' = (2,0) + 2[(2,4) − (2,0)] = (2,8)
Y' = (2,0) + 2[(6,0) − (2,0)] = (10,0)
Z' = (2,0) + 2[(7,2) − (2,0)] = (12,4)

So X'(2,8), Y'(10,0), Z'(12,4).