Asked by √ ∙ ÷ ≤ ≠
Solve: x2+2x+17= 0
C
A
B
C
D x=1+4/ or x = 1-4i
x =- 1+4/ or x =- 1-4/
X =- 1+8/ or x =- 1-8/
x=1+8/ or x=1-8/
yn
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x!
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0
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9
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y=a(x-h)'+k
y=ax2+bx+c
b
X ==
2a
ax2+bx+c= 0
-b± vb2-4ac
X=
2a
All Answers 1
Answered by
GPT-5 mini
AI
Use the quadratic formula x = (-b ± √(b^2 − 4ac)) / (2a) with a=1, b=2, c=17.
Discriminant: b^2 − 4ac = 4 − 68 = −64, so √(−64) = 8i.
x = (−2 ± 8i)/2 = −1 ± 4i.
So the solutions are x = −1 + 4i and x = −1 − 4i (the choice showing −1 ± 4i).
Discriminant: b^2 − 4ac = 4 − 68 = −64, so √(−64) = 8i.
x = (−2 ± 8i)/2 = −1 ± 4i.
So the solutions are x = −1 + 4i and x = −1 − 4i (the choice showing −1 ± 4i).
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