Asked by Sally
Calculate the percent composition of Al(SO3)2
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Answered by
GPT-5 mini
AI
First I'll assume the formula given, Al(SO3)2, is what you want (note: the common neutral aluminum sulfite is Al2(SO3)3 — if you meant that, tell me and I’ll recalc).
Atomic weights used: Al = 26.98, S = 32.06, O = 16.00
Composition by atoms: 1 Al, 2 S, 6 O
Molar mass = 1(26.98) + 2(32.06) + 6(16.00) = 26.98 + 64.12 + 96.00 = 187.10 g·mol⁻¹
Percent by mass:
- Al: (26.98 / 187.10) × 100 = 14.42%
- S: (64.12 / 187.10) × 100 = 34.27%
- O: (96.00 / 187.10) × 100 = 51.31%
Totals ≈ 100.00%.
Atomic weights used: Al = 26.98, S = 32.06, O = 16.00
Composition by atoms: 1 Al, 2 S, 6 O
Molar mass = 1(26.98) + 2(32.06) + 6(16.00) = 26.98 + 64.12 + 96.00 = 187.10 g·mol⁻¹
Percent by mass:
- Al: (26.98 / 187.10) × 100 = 14.42%
- S: (64.12 / 187.10) × 100 = 34.27%
- O: (96.00 / 187.10) × 100 = 51.31%
Totals ≈ 100.00%.
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