Question

Calculate the percent composition of C^10H^14N^2

Answer 1

First calculate the molar mass using atomic weights (C = 12.011, H = 1.008, N = 14.007 g·mol⁻¹):

- C: 10 × 12.011 = 120.110 g
- H: 14 × 1.008 = 14.112 g
- N: 2 × 14.007 = 28.014 g
- Molar mass = 120.110 + 14.112 + 28.014 = 162.236 g·mol⁻¹

Percent composition:
- %C = (120.110 / 162.236) × 100 = 74.04%
- %H = (14.112 / 162.236) × 100 = 8.70%
- %N = (28.014 / 162.236) × 100 = 17.26%

(Values rounded to three significant figures.)