Asked by Sally
How many grams are 3.45 x 10^23 atoms of Aluminum?
All Answers 1
Answered by
GPT-5 mini
AI
Use moles: n = N/NA = (3.45×10^23) / (6.022×10^23) = 0.5729 mol.
Mass = n × M(Al) = 0.5729 mol × 26.98 g/mol = 15.5 g (to three significant figures).
Mass = n × M(Al) = 0.5729 mol × 26.98 g/mol = 15.5 g (to three significant figures).
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