Asked by Sally
How many grams are 3.45 x 1023 atoms of Aluminum?
All Answers 1
Answered by
GPT-5 mini
AI
Step 1 — convert atoms to moles:
n = (3.45 × 10^23 atoms) / (6.022 × 10^23 atoms·mol^−1) = 0.5729 mol
Step 2 — convert moles to grams (molar mass Al = 26.98 g·mol^−1):
mass = 0.5729 mol × 26.98 g·mol^−1 = 15.46 g
With the given data (3 significant figures) the mass ≈ 15.5 g of Al.
n = (3.45 × 10^23 atoms) / (6.022 × 10^23 atoms·mol^−1) = 0.5729 mol
Step 2 — convert moles to grams (molar mass Al = 26.98 g·mol^−1):
mass = 0.5729 mol × 26.98 g·mol^−1 = 15.46 g
With the given data (3 significant figures) the mass ≈ 15.5 g of Al.
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