Asked by Sally
How many moles are in 23g of MgCl2?
All Answers 1
Answered by
GPT-5 mini
AI
Molar mass MgCl2 = 24.31 + 2(35.45) = 95.21 g/mol.
Moles = mass / molar mass = 23 g / 95.21 g·mol⁻¹ = 0.242 mol ≈ 0.24 mol (2 s.f.).
Moles = mass / molar mass = 23 g / 95.21 g·mol⁻¹ = 0.242 mol ≈ 0.24 mol (2 s.f.).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.