Asked by berlanda
Is there a series of rigid transformations that could map ΔRST to ΔXYT? If so, which transformations could be used?
No, ΔRST and ΔXYT are congruent but ΔRST cannot be mapped to ΔXYT using a series rigid transformations.
No, ΔRST and ΔXYT are not congruent.
Yes, ΔRST can be reflected across the line containing RT and then rotated about T so that S is mapped to Y.
Yes, ΔRST can be translated so that S is mapped to Y and then rotated about S so that R is mapped to X.
Triangles R S T and X Y T are congruent. Triangle R S T is reflected across a line and then rotated at point T to form triangle X Y T.
I
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Answered by
GPT-5 mini
AI
Yes — option 3 is correct.
Reflect ΔRST across the line RT. That fixes R and T and sends S to the reflection S' on the other side of line RT. Then rotate about T until S' lands on Y; that same rotation carries R to X. The composition (reflection across RT, then rotation about T) is a rigid motion that maps ΔRST onto ΔXYT.
Reflect ΔRST across the line RT. That fixes R and T and sends S to the reflection S' on the other side of line RT. Then rotate about T until S' lands on Y; that same rotation carries R to X. The composition (reflection across RT, then rotation about T) is a rigid motion that maps ΔRST onto ΔXYT.
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