Question

On a coordinate plane, an exponential function decreases from quadrant 2 into quadrant 1 and approaches y = 0. It crosses the y-axis at (0, 1).
Which function could be a stretch of the exponential decay function shown on the graph?

f(x) = 2(6)x
f(x) = One-half(6)x
f(x) = 2(one-sixth) Superscript x
f(x) = One-half (one-sixth) Superscript x

Answer 1

We need a decay function (base between 0 and 1). That rules out the options with base 6 (they grow to the right). The graph shows the basic decay (1/6)^x, and a "stretch" means a vertical stretch by a factor >1. So the correct choice is

f(x) = 2(1/6)^x.