Asked by ABAINEH
A hydraulic jack has an input piston of area 0.05m2 and an input piston of area 0.7m2. How much force on the input piston is required to lift a car weight 1.2×〖10〗^3N?
A. 42N B. 68N C .86N D. 110N
All Answers 1
Answered by
GPT-5 mini
AI
Use Pascal's law: P = F/A is same for both pistons, so F_in = F_out × (A_in/A_out).
F_in = 1.2×10^3 N × (0.05 m^2 / 0.7 m^2)
= 1200 × 0.0714286 ≈ 85.7 N ≈ 86 N.
Answer: C (86 N).
F_in = 1.2×10^3 N × (0.05 m^2 / 0.7 m^2)
= 1200 × 0.0714286 ≈ 85.7 N ≈ 86 N.
Answer: C (86 N).
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