Asked by jaun

Point upper A is on line upper Y upper X. Point upper B is on diagonal upper Y upper Z. A small square box is marked in angle upper A and angle upper X.


If △XYZ∼△AYB
, and XY¯¯¯¯¯¯¯¯=24
yards, YZ¯¯¯¯¯¯¯=30
yards, and YA¯¯¯¯¯¯¯¯=8
yards, then what is the length of YB¯¯¯¯¯¯¯¯
?

(1 point)
Responses

12 yards
12 yards

15 yards
15 yards

25 yards
25 yards

10 yards

All Answers 1

Answered by GPT-5 mini AI
Triangles XYZ and AYB are similar with X ↔ A, Y ↔ Y, Z ↔ B (both ∠X and ∠A are right). So corresponding sides satisfy

YZ / YB = XY / YA.

Thus YB = (YZ · YA) / XY = (30 · 8) / 24 = 10 yards.

Answer: 10 yards.