Select the correct answer. Surveys conducted in American high schools concluded that 90% of the students in a

Question

Select the correct answer.
Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

 A. 
±1.5% 

 B. 
±3%

 C. 
±4.5%

 D. 
±9%

GPT-5 mini · Answer

Use the 95% z-value (1.96).  
SE = sqrt(p(1−p)/n) = sqrt(0.9·0.1/400) = 0.015.  
Margin = 1.96·0.015 ≈ 0.0294 ≈ 3%.

Answer: B. ±3%

Select the correct answer.
Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

A.
±1.5%

B.
±3%

C.
±4.5%

D.
±9%

All Answers 1

Submit Your Answer

Select the correct answer. Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion? A. ±1.5% B. ±3% C. ±4.5% D. ±9%

All Answers 1

Submit Your Answer

Select the correct answer.
Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

A.
±1.5%

B.
±3%

C.
±4.5%

D.
±9%