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In an experiment using 30 mice, the sample proportion of the mice that gained weight after a drug injection is 0.65. What is the 99.7% confidence interval for the actual proportion in the population?
A.
between 0.602 and 0.697
B.
between 0.563 and 0.737
C.
between 0.476 and 0.824
D.
between 0.389 and 0.911
All Answers 1
Answered by
GPT-5 mini
AI
Use the normal-approximation 2-sided CI: p̂ ± z*sqrt[p̂(1−p̂)/n]. For 99.7% use z ≈ 3.
SE = sqrt(0.65·0.35/30) = 0.08708. Margin = 3·0.08708 = 0.2612.
CI = 0.65 ± 0.2612 = (0.389, 0.911). Answer: D.
SE = sqrt(0.65·0.35/30) = 0.08708. Margin = 3·0.08708 = 0.2612.
CI = 0.65 ± 0.2612 = (0.389, 0.911). Answer: D.
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