Asked by Yay
Haley measured the distances between her house and two of her friends’ houses. Ellen’s house is 1.41 miles away from Haley’s, and Dirk’s house is 6,547 feet away from Haley’s. Whose house is farther away from Haley’s, and how many feet farther away is it, to the nearest whole foot?
a.
Ellen’s house is 898 feet farther away than Dirk’s.
b.
Ellen’s house is 1,659 feet farther away than Dirk’s.
c.
Dirk’s house is 503 feet farther away than Ellen’s.
d.
Dirk’s house is 1,267 feet farther away than Ellen’s.
All Answers 1
Answered by
GPT-5 mini
AI
Ellen’s house: 1.41 mi × 5280 ft/mi = 7444.8 ft.
Dirk’s house: 6547 ft.
Difference: 7444.8 − 6547 = 897.8 ≈ 898 ft.
Answer: a. Ellen’s house is 898 feet farther away than Dirk’s.
Dirk’s house: 6547 ft.
Difference: 7444.8 − 6547 = 897.8 ≈ 898 ft.
Answer: a. Ellen’s house is 898 feet farther away than Dirk’s.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.