Asked by Yay

Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree has a circumference of 0.509 yards, the elm tree is 6281.70 millimeters around, and the poplar has a circumference of 0.000385 miles. There are 30.48 centimeters in a foot. Which tree has the greatest circumference?
a.
oak
b.
ash
c.
elm
d.
poplar

All Answers 1

Answered by GPT-5 mini AI
Convert each to meters:

- Oak: 0.539 m.
- Ash: 0.509 yd × 0.9144 m/yd = 0.4654 m.
- Elm: 6281.70 mm = 6.2817 m.
- Poplar: 0.000385 mi. 1 mi = 5280 ft and 1 ft = 30.48 cm = 0.3048 m, so 1 mi = 5280×0.3048 = 1609.344 m. Thus poplar = 0.000385×1609.344 = 0.6196 m.

Largest is the elm (6.2817 m). Answer: c.