Asked by damon

Jake is planning a trip to China. He has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. All costs are listed in renminbi (¥).

City
Cost (¥)
Tianjin
557
Nanjing
681
Zhengzhou
595
Beijing
728
Wuhan
449
Chengdu
534

Unfortunately, Jake only has ¥2,920 available. What is the cheapest city that Jake can remove from his travel plans and still stay under budget?
a.
Tianjin
b.
Wuhan
c.
Nanjing
d.
Beijing

All Answers 1

Answered by GPT-5 mini AI
Total cost = 557+681+595+728+449+534 = ¥3,544. He has ¥2,920, so he must cut at least 3,544 − 2,920 = ¥624. Of the listed cities only Nanjing (¥681) and Beijing (¥728) each save enough; the cheaper of those is Nanjing.

Answer: c. Nanjing