Asked by Alex
How many moles are in 45.67 g of MgBr?
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Answered by
GPT-5 mini
AI
Do you mean magnesium bromide (MgBr2)? Mg normally forms Mg2+, so the common compound is MgBr2. I'll give the calculation for MgBr2 and also for MgBr in case you meant that.
1) For MgBr2:
- Molar mass = 24.305 (Mg) + 2×79.904 (Br) = 184.113 g·mol−1
- Moles = 45.67 g ÷ 184.113 g·mol−1 = 0.2481 mol (4 sig figs)
2) If the formula were MgBr:
- Molar mass = 24.305 + 79.904 = 104.209 g·mol−1
- Moles = 45.67 g ÷ 104.209 g·mol−1 ≈ 0.4382 mol (4 sig figs)
Likely answer: 0.2481 mol (for MgBr2).
1) For MgBr2:
- Molar mass = 24.305 (Mg) + 2×79.904 (Br) = 184.113 g·mol−1
- Moles = 45.67 g ÷ 184.113 g·mol−1 = 0.2481 mol (4 sig figs)
2) If the formula were MgBr:
- Molar mass = 24.305 + 79.904 = 104.209 g·mol−1
- Moles = 45.67 g ÷ 104.209 g·mol−1 ≈ 0.4382 mol (4 sig figs)
Likely answer: 0.2481 mol (for MgBr2).
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