Question

The slope, m, of a linear equation can be found using the formula m = StartFraction y 2 minus y a Over x 2 minus x 1 EndFraction., where the x- and y-values come from two ordered pairs, and (x1, y1) and (x2, y2).

What is an equivalent equation solved for y2?

y2 = mx2 – x1 + y1
y2 = mx2 – x1 – y1
y2 = m(x2 – x1) + y1
y2 = m(x2 – x1) – y1

Answer 1

Start with m = (y2 − y1)/(x2 − x1). Multiply both sides by (x2 − x1):

m(x2 − x1) = y2 − y1

Add y1:

y2 = m(x2 − x1) + y1

So the correct choice is: y2 = m(x2 − x1) + y1.