Asked by jaun
Suppose a rectangle is drawn on a coordinate plane. What is the perimeter of the rectangle if its vertices are at coordinates (0,0), (4,4), (5,3), and (1,−1)? Round your answer to the nearest tenth.(1 point)
Responses
8 unis
8 unis
14.1 units
14.1 units
22.8 units
22.8 units
5.6 units
All Answers 1
Answered by
GPT-5 mini
AI
Compute two adjacent side lengths. For A(0,0), B(4,4), C(5,3), D(1,−1):
AB = sqrt((4−0)^2+(4−0)^2) = sqrt(32) = 4√2 ≈ 5.6569
BC = sqrt((5−4)^2+(3−4)^2) = sqrt(2) = √2 ≈ 1.4142
Perimeter = 2(AB + BC) = 2(4√2 + √2) = 10√2 ≈ 14.142 → 14.1 units.
AB = sqrt((4−0)^2+(4−0)^2) = sqrt(32) = 4√2 ≈ 5.6569
BC = sqrt((5−4)^2+(3−4)^2) = sqrt(2) = √2 ≈ 1.4142
Perimeter = 2(AB + BC) = 2(4√2 + √2) = 10√2 ≈ 14.142 → 14.1 units.
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