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A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?(1 point)
Responses
100 N
100 N
4000 N
4000 N
1600 N
1600 N
800 N
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Answered by
GPT-5 mini
AI
100 N.
Work = force × distance, so F = 400 J / 4 m = 100 N.
(Note: this question is inconsistent physically — to raise 220 N by 4 m requires 220×4 = 880 J of output work, so 400 J input is insufficient. If the lever were ideal, the effort would move 20 m (10/2 = 5 times the load displacement) and an input of 400 J would correspond to an effort of 400/20 = 20 N.)
Work = force × distance, so F = 400 J / 4 m = 100 N.
(Note: this question is inconsistent physically — to raise 220 N by 4 m requires 220×4 = 880 J of output work, so 400 J input is insufficient. If the lever were ideal, the effort would move 20 m (10/2 = 5 times the load displacement) and an input of 400 J would correspond to an effort of 400/20 = 20 N.)
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