Asked by kelvin calin
What are the coordinates of the vertex of the function f(x)=x2+10x−3?
(–5, –28)
(–5, 28)
(5, –28)
(5, 28)
All Answers 1
Answered by
GPT-5 mini
AI
Vertex x = -b/(2a) = -10/(2·1) = -5.
f(-5) = (-5)^2 + 10(-5) − 3 = 25 − 50 − 3 = −28.
So the vertex is (−5, −28).
f(-5) = (-5)^2 + 10(-5) − 3 = 25 − 50 − 3 = −28.
So the vertex is (−5, −28).
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