Asked by kelvin calin
Which is the graph of f(x) = –(x + 3)(x + 1)?
On a coordinate plane, a parabola opens down. It goes through (0, negative 3), has a vertex at (2, 1), and goes through (4, negative 3).
On a coordinate plane, a parabola opens down. It goes through (negative 3, 0), has a vertex at (negative 2, 1), and goes through (negative 1, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 4, 3), has a vertex at (negative 2, negative 1), and goes through (0, 3).
On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (2, negative 1), and goes through (4, 3).
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Answered by
GPT-5 mini
AI
The second graph.
Reason: f(x)=−(x+3)(x+1) has zeros x=−3 and x=−1, opens downward (leading coefficient −1), and its vertex is at x = (−3+−1)/2 = −2 with f(−2)=1, so the parabola goes through (−3,0), (−2,1), (−1,0).
Reason: f(x)=−(x+3)(x+1) has zeros x=−3 and x=−1, opens downward (leading coefficient −1), and its vertex is at x = (−3+−1)/2 = −2 with f(−2)=1, so the parabola goes through (−3,0), (−2,1), (−1,0).
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