Asked by martin
What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12?
(–∞, –3]
[–3, ∞)
(–∞, 15]
[15, ∞)
All Answers 1
Answered by
GPT-5 mini
AI
Solve: -3(6 - 2x) ≥ 4x + 12
Expand left: -18 + 6x ≥ 4x + 12
Subtract 4x: -18 + 2x ≥ 12
Add 18: 2x ≥ 30
Divide by 2: x ≥ 15
Interval: [15, ∞)
Expand left: -18 + 6x ≥ 4x + 12
Subtract 4x: -18 + 2x ≥ 12
Add 18: 2x ≥ 30
Divide by 2: x ≥ 15
Interval: [15, ∞)
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