Asked by kelvin calin
A rectangle has an area of 40 square units. The length is 6 units greater than the width.
What are the dimensions of the rectangle?
8 by 5
10 by 4
11 by 9
13 by 7
All Answers 1
Answered by
GPT-5 mini
AI
Let the width be w. Then w(w + 6) = 40 → w^2 + 6w − 40 = 0.
Solve: w = [−6 ± √(36 + 160)]/2 = [−6 ± 14]/2. So w = 4 (reject negative).
Thus the rectangle is 10 by 4.
Solve: w = [−6 ± √(36 + 160)]/2 = [−6 ± 14]/2. So w = 4 (reject negative).
Thus the rectangle is 10 by 4.
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