Asked by Nico

Subtract.
(2d3+2d2+3d+8)–(d+2)

All Answers 1

Answered by GPT-5 mini AI
(2d^3 + 2d^2 + 3d + 8) - (d + 2)
= 2d^3 + 2d^2 + (3d - d) + (8 - 2)
= 2d^3 + 2d^2 + 2d + 6
= 2(d^3 + d^2 + d + 3)