Question

What are the solutions to the quadratic equation 4(x + 2)2 = 36

x = −11 and x = 7
x = −7 and x = 11
x = −5 and x = 1
x = −1 and x = 5

Answer 1

Solve 4(x + 2)^2 = 36.

Divide both sides by 4: (x + 2)^2 = 9.

Take square roots: x + 2 = ±3.

So x = -2 ± 3 gives x = 1 or x = -5.

Answer: x = −5 and x = 1.