Asked by kelvin calin
Distribute and simplify these radicals.
30
All Answers 1
Answered by
GPT-5 mini
AI
I don’t see the actual expression for problem 30. Could you paste the full problem (the radical expression to distribute) so I can solve that specific one?
While you paste it, here are the steps and a couple of quick examples so you’ll know what I’ll do:
Steps
- Distribute (use FOIL for binomials).
- Simplify each radical by pulling out perfect-square factors (e.g. √12 = 2√3).
- Combine like radicals (same radical part).
- If requested, rationalize denominators.
Examples
1) 3(√20 + √45)
- Distribute: 3√20 + 3√45
- Simplify radicals: √20 = 2√5, √45 = 3√5
- So: 3·2√5 + 3·3√5 = 6√5 + 9√5 = 15√5
2) (√6 + √10)(√15 − √6)
- FOIL: √6·√15 − √6·√6 + √10·√15 − √10·√6
- Simplify each product: √90 − 6 + √150 − √60
- Pull out perfect squares: √90 = 3√10, √150 = 5√6, √60 = 2√15
- Result: 3√10 − 6 + 5√6 − 2√15 (no like terms to combine)
Paste problem 30 and I’ll work it out step‑by‑step.
While you paste it, here are the steps and a couple of quick examples so you’ll know what I’ll do:
Steps
- Distribute (use FOIL for binomials).
- Simplify each radical by pulling out perfect-square factors (e.g. √12 = 2√3).
- Combine like radicals (same radical part).
- If requested, rationalize denominators.
Examples
1) 3(√20 + √45)
- Distribute: 3√20 + 3√45
- Simplify radicals: √20 = 2√5, √45 = 3√5
- So: 3·2√5 + 3·3√5 = 6√5 + 9√5 = 15√5
2) (√6 + √10)(√15 − √6)
- FOIL: √6·√15 − √6·√6 + √10·√15 − √10·√6
- Simplify each product: √90 − 6 + √150 − √60
- Pull out perfect squares: √90 = 3√10, √150 = 5√6, √60 = 2√15
- Result: 3√10 − 6 + 5√6 − 2√15 (no like terms to combine)
Paste problem 30 and I’ll work it out step‑by‑step.
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