Asked by unknown
Quadrilateral $QRST$ has vertices at $Q(−1, 5)$, $R(2, 8)$, $S(4, 4)$, and $T(1, 1)$. The measure of Angle $Q$ is $108^\circ$ and the measure of angle $R$ is $108 - 2x$Is this a parallelogram?Responses
1-yes
2-no
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
1 — yes.
Reason: QR = (3,3) and ST = (−3,−3) (parallel/opposite), RS = (2,−4) and TQ = (−2,4) (parallel/opposite), so opposite sides are parallel — it's a parallelogram.
Also, in a parallelogram adjacent angles are supplementary: 108 + (108 − 2x) = 180 ⇒ x = 18.
Reason: QR = (3,3) and ST = (−3,−3) (parallel/opposite), RS = (2,−4) and TQ = (−2,4) (parallel/opposite), so opposite sides are parallel — it's a parallelogram.
Also, in a parallelogram adjacent angles are supplementary: 108 + (108 − 2x) = 180 ⇒ x = 18.
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