Asked by kelvin calin
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(6) EndRoot Over 2(3) EndFraction
x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4 (3)(6) EndRoot Over 2(3) EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
The first one is correct.
From 0 = −3x^2 − 2x + 6 we have a = −3, b = −2, c = 6, so
x = (−(−2) ± √((−2)^2 − 4(−3)(6))) / (2(−3)).
You can simplify: b^2 − 4ac = 4 + 72 = 76, so
x = (2 ± √76)/(−6) = −(1 ± √19)/3.
From 0 = −3x^2 − 2x + 6 we have a = −3, b = −2, c = 6, so
x = (−(−2) ± √((−2)^2 − 4(−3)(6))) / (2(−3)).
You can simplify: b^2 − 4ac = 4 + 72 = 76, so
x = (2 ± √76)/(−6) = −(1 ± √19)/3.
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