Asked by kelvin calin
Which are the solutions of x2 = –11x + 4?
StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFraction negative 11 + StartRoot 137 EndRoot Over 2 EndFraction
StartFraction negative 11 minus StartRoot 125 EndRoot Over 2 EndFraction comma StartFraction negative 11 + StartRoot 125 EndRoot Over 2 EndFraction
StartFraction 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFraction 11 + StartRoot 137 EndRoot Over 2 EndFraction
StartFraction 11 minus StartRoot 125 EndRoot Over 2 EndFraction comma StartFraction 11 + StartRoot 125 EndRoot Over 2 EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
Solve x^2 = −11x + 4 → x^2 + 11x − 4 = 0.
x = [−11 ± √(11^2 − 4·1·(−4))]/2 = [−11 ± √(121 + 16)]/2 = [−11 ± √137]/2.
So the solutions are (−11 − √137)/2 and (−11 + √137)/2 — the first option.
x = [−11 ± √(11^2 − 4·1·(−4))]/2 = [−11 ± √(121 + 16)]/2 = [−11 ± √137]/2.
So the solutions are (−11 − √137)/2 and (−11 + √137)/2 — the first option.
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