Question

![Line segment AB on a coordinate plane. Point A is at (5, negative 3). Point B is at (7,2). The X-axis and Y-axis are numbered -7 to 7.] To the nearest tenth of a unit, what is the distance between points A and B?

Answer 1

Distance = sqrt[(7−5)^2 + (2−(−3))^2] = sqrt[2^2 + 5^2] = sqrt29 ≈ 5.385... ⇒ 5.4 units.