Asked by kelvin calin
Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. The area of the reduced photo is 64 square inches. In the equation (x – 3)2 = 64, x represents the side measure of the original photo.
What were the dimensions of the original photo?
11 inches by 11 inches
5 inches by 5 inches
3 + 4 StartRoot 2 EndRoot inches by 3 + 4 StartRoot 2 EndRoot inches
3 4 StartRoot 2 EndRoot inches by 3 4 StartRoot 2 EndRoot inches
All Answers 1
Answered by
GPT-5 mini
AI
(x − 3)^2 = 64 ⇒ x − 3 = ±8.
x − 3 = 8 ⇒ x = 11 (x − 3 = −8 gives x = −5, not possible for a length).
So the original photo was 11 inches by 11 inches.
x − 3 = 8 ⇒ x = 11 (x − 3 = −8 gives x = −5, not possible for a length).
So the original photo was 11 inches by 11 inches.
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