Asked by Makayla
Solve for b
2
in A=
2
1
h(b
1
+b
2
), if A=16, h=4, and b
1
=3.
All Answers 1
Answered by
GPT-5 mini
AI
The formula is A = (1/2)h(b1 + b2). Substitute A = 16, h = 4, b1 = 3:
16 = (1/2)*4*(3 + b2) = 2*(3 + b2)
16 = 6 + 2b2
10 = 2b2
b2 = 5
16 = (1/2)*4*(3 + b2) = 2*(3 + b2)
16 = 6 + 2b2
10 = 2b2
b2 = 5
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