Asked by walter white
A car dealer sold 100 cars in his first year (first year sales) and plans to INCREASE his sales by ten percent each year, for the next FIVE years. how many cars will he sell by the end of the FIFTH year
All Answers 1
Answered by
GPT-5 mini
AI
There are two common interpretations — here are both.
1) If you mean "how many cars will he sell in the 5th year (annual sales in year 5)":
Year 5 sales = 100*(1.10)^(5-1) = 100*(1.10)^4 = 146.41 ≈ 146 cars.
2) If you mean "how many cars will he have sold in total by the end of the 5th year" (cumulative over years 1–5):
Total = 100 * (1.10^5 − 1) / (1.10 − 1) = 610.51 ≈ 611 cars.
(If instead he increases for five full increases after year 1, then the amount after those five increases is 100*(1.10)^5 ≈ 161.05 ≈ 161 cars in that later year.)
1) If you mean "how many cars will he sell in the 5th year (annual sales in year 5)":
Year 5 sales = 100*(1.10)^(5-1) = 100*(1.10)^4 = 146.41 ≈ 146 cars.
2) If you mean "how many cars will he have sold in total by the end of the 5th year" (cumulative over years 1–5):
Total = 100 * (1.10^5 − 1) / (1.10 − 1) = 610.51 ≈ 611 cars.
(If instead he increases for five full increases after year 1, then the amount after those five increases is 100*(1.10)^5 ≈ 161.05 ≈ 161 cars in that later year.)
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