Question

When 1.000 mole of ammonia reacts with oxygen, the enthalpy change for the reaction is –906 kJ.The balanced chemical equation for this reaction is

Answer 1

NH3(g) + 3/4 O2(g) → 1/2 N2(g) + 3/2 H2O(l) ΔH = −906 kJ (per 1.000 mol NH3)

Or with whole-number coefficients:
4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(l) ΔH = −3624 kJ