Asked by huhhf3;q

A mass is attached to a spring. The rest position of the spring is 45 cm. The mass is hen pulled to stretch the spring to a position of 51 cm. If the spring constant is 805 N/m.
What is the elastic potential energy in this spring at this point?
Answer:
5) What is the first law of Thermodynamics?
Answer:
6) What formula would you use for law of conservation of mechanical energy?
Answer:
7) What equations could be included in a problem with law of conservation of energy if there is a spring shooting an object that is above zero meters
two sentences each

All Answers 1

Answered by GPT-5 mini AI
1) Elastic potential energy:
U = 1/2 k x^2 with x = 51 cm − 45 cm = 6 cm = 0.06 m.
U = 0.5(805 N/m)(0.06 m)^2 = 1.45 J (approximately).

5) What is the first law of Thermodynamics?
The first law states that the change in internal energy of a system equals the heat added to the system minus the work done by the system: ΔU = Q − W. This expresses conservation of energy for thermodynamic processes, accounting for heat and work transfers.

6) What formula would you use for law of conservation of mechanical energy?
For a closed system with only conservative forces, use KE + PE = constant, or 1/2 m v_i^2 + m g h_i + 1/2 k x_i^2 = 1/2 m v_f^2 + m g h_f + 1/2 k x_f^2. This states that kinetic plus potential energies (gravitational and elastic) are conserved.

7) What equations could be included in a problem with law of conservation of energy if there is a spring shooting an object that is above zero meters?
Include elastic potential energy U_spring = 1/2 k x^2, gravitational potential energy U_grav = m g h, and kinetic energy KE = 1/2 m v^2; then set initial total energy equal to final total energy: 1/2 k x_i^2 + m g h_i + 1/2 m v_i^2 = 1/2 k x_f^2 + m g h_f + 1/2 m v_f^2. If nonconservative forces (e.g., friction) are present, add/subtract their work as ΔE_mech = −W_nc (or include +W_nc on the appropriate side).